Golang中如何使用lua进行扩展详解

str := "hello"
num := 10
L.LString(str)
L.LNumber(float64(num))

value := L.Get(1)
switch value.Type() {
case lua.LTString:
case lua.LTTable:
....
}

func hello(L *lua.State) int {
  //将返回参数压入栈中
  L.Push(lua.LString("hello"))
  //返回参数为1个
  return 1
}
//注入lua中
L.SetGlobal("hello", L.NewFunction(hello))

//先获取lua中定义的函数
fn := L.GetGlobal("hello")
if err := L.CallByParam(lua.P{
 Fn: fn,
 NRet: 1,
 Protect: true,
 }, lua.LNumber(10)); err != nil {
 panic(err)
}
//这里获取函数返回值
ret := L.Get(-1)

type Role struct {
 Name string
}

type Person struct {
 Name  string
 Age  int
 WorkPlace string
 Role  []*Role
}

L := lua.NewState()
if err := L.DoString(`
person = {
 name = "Michel",
 age = "31", -- weakly input
 work_place = "San Jose",
 role = {
 {
  name = "Administrator"
 },
 {
  name = "Operator"
 }
 }
}
`); err != nil {
 panic(err)
}
var person Person
if err := gluamapper.Map(L.GetGlobal("person").(*lua.LTable), &person); err != nil {
 panic(err)
}
fmt.Printf("%s %d", person.Name, person.Age)

func Loader(L *lua.LState) int {
 //注册模块中的导出函数
 mod := L.SetFuncs(L.NewTable(), exports)
 L.Push(mod)
 return 1
}

var exports = map[string]lua.LGFunction{
 "myfunc": myfunc,
}

func myfunc(L *lua.LState) int {
 return 0
}
//这里就可以加载mymodule模块
L.PreloadModule("mymodule", mymodule.Loader)