Matplotlib scatter绘制散点图的方法实现

import numpy as np
import matplotlib.pyplot as plt

#生成散点数据
n = 1024
X = np.random.normal(0,1,n)
Y = np.random.normal(0,1,n)

plt.scatter(X,Y)  #输入散点数据
plt.show()     #显示散点图

import numpy as np
import matplotlib.pyplot as plt

fig, ax = plt.subplots()

for color in ['red', 'green', 'purple']:      #每一次循环都会产生一组散点数据
  n = 400
  x = np.random.normal(0,1,n)
  y = np.random.normal(0,1,n)
  ax.scatter(x, y, c=color, label=color ,alpha=0.5)

ax.legend()                     #显示图例

plt.show()

#函数定义看看就好了
def subplots(nrows=1, ncols=1, sharex=False, sharey=False, squeeze=True,
       subplot_kw=None, gridspec_kw=None, **fig_kw):
  fig = figure(**fig_kw)
  axs = fig.subplots(nrows=nrows, ncols=ncols, sharex=sharex, sharey=sharey,
            squeeze=squeeze, subplot_kw=subplot_kw,
            gridspec_kw=gridspec_kw)
  return fig, axs

import numpy as np
import matplotlib.pyplot as plt

n = 30

x = np.random.normal(0,1,n)
y = np.random.normal(0,1,n)

plt.subplot(321)
plt.scatter(x, y, s=80, c='red', marker='^')

plt.subplot(322)
plt.scatter(x, y, s=80, c='green', marker=(7, 1))

plt.subplot(323)
plt.scatter(x, y, s=1, c='purple', marker=(6, 1))

plt.subplot(324)
plt.scatter(x, y, s=400, c='red', marker=(5, 1))

plt.subplot(325)
plt.scatter(x, y, s=80, c='green', marker='+')

plt.subplot(326)
plt.scatter(x, y, s=80, c='purple', marker=(5, 2))

plt.show()