python实现将列表中各个值快速赋值给多个变量
我就废话不多说啦,还是直接看代码吧!
list1 = [1,2,3,4]
a,b,c,d = list1
则
a = 1
b =2
等
这种方式只有当左边的操作数个数和list1长度相同时,才可以这么做,不然报错.
我们假设我们有一个list对象List,它的长度足够长,想把它从下标i开始的k个元素赋给k个元素,可以这么做:
v1, v2, v3, …, vk = List[i : i + k] #默认i=0, k=len(List)
补充知识:python 将某个字段存储为列表类型
实现存储数据格式为
{ "_index": "nested-20180815", "_type": "stb-iptv-montor-m-gather-apk", "_id": "AWU8sZboGQQbsn0rAW4J", "_score": 1, "_source": { "mdiNested": [ { "mdiMLR": 0, "mdiType": "0" }, { "mdiMLR": 0, "mdiType": "1" }, { "mdiMLR": 0, "mdiType": "2" }, { "mdiMLR": 0, "mdiType": "3" }, { "mdiMLR": 0, "mdiType": "4" }, { "mdiMLR": 0, "mdiType": "5" } ] } }
代码:
from elasticsearch import Elasticsearch from elasticsearch import helpers import json es_20 = Elasticsearch(hosts="1.0.0.0", port=9200, timeout=15000) time_ = "20180815" index_20 = "nested-{0}".format(time_) type_20 = "stb-iptv-montor-m-gather-apk" def set_mapping(): my_mappping = { type_20: { "properties": { "mdiNested": { "properties": { "mdiMLR": { "type": "short" }, "mdiType": { "type": "keyword" } } } } } } create_index = es_20.indices.create(index=index_20, body=None) create_mapping = es_20.indices.put_mapping(index=index_20, body=my_mappping, doc_type=type_20) mdiMLR = [0,1,2,3,4] mdiType = ["0","1","2","3","4","5"] actions = [] dict_ ={} for mdiMLR_ in mdiMLR: dict_list = [] for type in mdiType: t1 ={'mdiMLR': mdiMLR_, 'mdiType': type} dict_list.append(t1) action = { "_index": index_20, "_type": type_20, "_source": { "mdiNested": dict_list } } actions.append(action) helpers.bulk(es_20, actions)
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