Java实战之用Spring开发条形码和验证码
更新时间:2021年04月29日 09:02:32 作者:风轻仰
这篇文章主要介绍了Java实战之用Spring开发条形码和验证码,文中有非常详细的代码示例,对正在学习java的小伙伴们有非常好的帮助,需要的朋友可以参考下
一、条形码
代码如下:
import javax.swing.*; import java.awt.*; import java.awt.image.BufferedImage; import java.util.Random; public class Text extends JFrame { private static final int WIDTH=300;//窗口的宽度 private static final int HEIGHT=400;//窗口的高度 private static final int LINES=120;//内部的线条数量 private static final int SPACE=10;//线条与线条之间的间距 private static JFrame jFrame=null; public static void main(String[] args) { initialize(); } private static void initialize(){//初始化窗口 jFrame=new JFrame("条形码"); jFrame.setSize(WIDTH,HEIGHT); jFrame.setLayout(null); JLabel jLabel=new JLabel(); jLabel.setBounds(0,0,WIDTH,80); jLabel.setIcon(new ImageIcon(setCode())); jFrame.add(jLabel); jFrame.setVisible(true); jFrame.setLocationRelativeTo(null); jFrame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); } private static BufferedImage setCode() { Random random = new Random(); BufferedImage bufferedImage = new BufferedImage(WIDTH, 80, BufferedImage.TYPE_INT_RGB);//创建一个图片画板 Graphics g = bufferedImage.getGraphics();//得到画笔 g.setColor(Color.white);//设置画笔颜色 g.fillRect(0, 0, WIDTH, 80);//规定画笔的一个范围 g.setColor(Color.black);//这个是设置线条的颜色 for(int i=0;i<LINES;i++){ int row=random.nextInt(WIDTH)+SPACE; g.drawLine(row,0,row,HEIGHT); } return bufferedImage; } }
效果如下:
二、验证码
代码如下:
import javax.swing.*; import java.awt.*; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.awt.event.MouseAdapter; import java.awt.event.MouseEvent; import java.awt.image.BufferedImage; import java.util.Random; public class Text extends JFrame{ private final static char[] words=("1234567890" + "abcdefghijklmnopqrstuvwxyz" + "ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray(); private final static int WORDLENGTH=4; private final static int WIDTH=200; private final static int HEIGHT=100; private final static int STAR=200; private static Text t=null; private static TextField textFile=null; private static Object[] obj=null; private static Object[] drawCode(){ BufferedImage bufferedImage=new BufferedImage(WIDTH,HEIGHT,BufferedImage.TYPE_INT_RGB); Graphics g=bufferedImage.getGraphics(); char[] selectWord=new char[4]; g.setColor(Color.LIGHT_GRAY); g.fillRect(0,0,WIDTH,HEIGHT); Random random=new Random(); for(int i=0;i<WORDLENGTH;i++){ int n=random.nextInt(words.length); selectWord[i]=words[i]; g.setFont(new Font("微软雅黑",0,random.nextInt(20)+40)); g.setColor(setRandomColor()); g.drawString(words[n]+"",i*WIDTH/WORDLENGTH,HEIGHT/2+10); } for(int i=0;i<STAR;i++){ g.setColor(setRandomColor()); g.setFont(new Font("楷书",0,40)); g.drawOval(random.nextInt(WIDTH),random.nextInt(HEIGHT),3, 3); } return new Object[]{selectWord,bufferedImage}; } private static Color setRandomColor(){ Random colorRandom=new Random(); return new Color(colorRandom.nextInt(256),colorRandom.nextInt(256),colorRandom.nextInt(256)); } public static void main(String[] args) { t=new Text(); t.setLocationRelativeTo(null); t.setSize(WIDTH,200); t.setLayout(null); t.add(setLabel()); t.add(setButton()); t.add(setTextField()); t.setVisible(true); t.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); } private static JLabel setLabel(){ JLabel jLabel=new JLabel(); obj=drawCode(); jLabel.setIcon(new ImageIcon((BufferedImage)obj[1])); jLabel.setBounds(0,0,WIDTH,HEIGHT); jLabel.addMouseListener(new MouseAdapter() { @Override public void mouseClicked(MouseEvent e) { jLabel.setIcon(new ImageIcon((BufferedImage)drawCode()[1])); } }); return jLabel; } private static TextField setTextField(){ textFile=new TextField(); textFile.setFont(new Font("华文行楷",0,20)); textFile.setBounds(5,120, 100,30); return textFile; } private static JButton setButton(){ JButton jButton=new JButton("检测"); jButton.setBounds(110,120, 70,30); jButton.addActionListener(new ActionListener() { @Override public void actionPerformed(ActionEvent e) { System.out.println(textFile.getText().equals(obj[0])); } }); return jButton; } }
效果如下:
验证码这里是因为没有设置好字符编码的原因,让中文字符无法在窗口内不显示
验证码就比条形码难以点点,但是基本的编写思想都是差不多的,
但最难的还是在二维码上,编写二维码就需要要求编写者的算法能力足够的扎实,而且还要有足够丰富的Java功底
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