C++实现LeetCode(121.买卖股票的最佳时间)
[LeetCode] 121.Best Time to Buy and Sell Stock 买卖股票的最佳时间
Say you have an array for which the ith element is the price of a given stock on day i.
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.
这道题相当简单,感觉达不到Medium的难度,只需要遍历一次数组,用一个变量记录遍历过数中的最小值,然后每次计算当前值和这个最小值之间的差值最为利润,然后每次选较大的利润来更新。当遍历完成后当前利润即为所求,代码如下:
C++ 解法:
class Solution { public: int maxProfit(vector<int>& prices) { int res = 0, buy = INT_MAX; for (int price : prices) { buy = min(buy, price); res = max(res, price - buy); } return res; } };
Java 解法:
public class Solution { public int maxProfit(int[] prices) { int res = 0, buy = Integer.MAX_VALUE; for (int price : prices) { buy = Math.min(buy, price); res = Math.max(res, price - buy); } return res; } }
类似题目:
Best Time to Buy and Sell Stock with Cooldown
Best Time to Buy and Sell Stock IV
Best Time to Buy and Sell Stock III
Best Time to Buy and Sell Stock II
到此这篇关于C++实现LeetCode(121.买卖股票的最佳时间)的文章就介绍到这了,更多相关C++实现买卖股票的最佳时间内容请搜索脚本之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持脚本之家!
相关文章
Ubuntu16.04下配置VScode的C/C++开发环境
这篇文章主要介绍了Ubuntu16.04下配置VScode的C/C++开发环境的教程,本文通过图文并茂的形式给大家介绍的非常详细,对大家的学习或工作具有一定的参考借鉴价值,需要的朋友可以参考下2020-03-03
最新评论