C++实现T型插补详解
更新时间:2021年10月29日 08:47:57 作者:(CKK)
这篇文章主要介绍了C++实现T型插补,本文给大家介绍的非常详细,对大家的学习或工作具有一定的参考借鉴价值,需要的朋友可以参考下
Tspeed.h程序
#pragma once #ifndef TSPEED_H #define TSPEED_H #include<iostream> #include<fstream> #include<cmath> using namespace std; void Tspeed(); #endif //TSPEED_H!
Tspeed.cpp程序
#include "Tspeed.h" ofstream out("Tspeed.txt", ios_base::ate); void Tspeed() { double v0 = 50, v1 = 20, vmax = 150; double a_add = 1000, a_dec = -1500; double p0 = 5, p1 = 30; double t0 = 2; double h = p1 - p0; double vf, vv; double step = 0.001; vf = sqrt((2 * a_add * a_dec * h - a_add * pow(v1, 2) + a_dec * pow(v0, 2)) / (a_dec - a_add)); if (vf < vmax) { vv = vf; } else { vv = vmax; } double Ta, Tv, Td; double La, Lv, Ld; Ta = (vv - v0) / a_add; Tv = (h - (pow(vv, 2) - pow(v0, 2)) / (2 * a_add) - (pow(v1, 2) - pow(vv, 2)) / (2 * a_dec)) / vv; Td = (v1 - vv) / a_dec; double t1; t1 = t0 + Ta + Tv + Td; La = v0 * Ta + 0.5 * a_add * pow(Ta, 2); Lv = vv * Tv; Ld = vv * Td + 0.5 * a_dec * pow(Td, 2); double p, pd, pdd; for (double t = 0; t <= Ta + Tv + Td;) { if (t >= 0 && t < Ta) { p = p0 + v0 * t + 0.5 * a_add * pow(t, 2); pd = v0 + a_add * t; pdd = a_add; } else if (t >= Ta && t < Ta + Tv) { p = p0 + La + vv * (t - Ta); pd = vv; pdd = 0; } else if (t >= Ta + Tv && t <= Ta + Tv + Td) { p = p0 + La + Lv + vv * (t - Ta - Tv) + 0.5 * a_dec * pow((t - Ta - Tv), 2); pd = vv + a_dec * (t - Ta - Tv); pdd = a_dec; } t = t + step; double temp = 2; temp = temp + t; cout << temp << " " << p << " " << pd << " " << pdd << " " << endl; out << temp << " " << p << " " << pd << " " << pdd << " " << endl; //cout << t << endl; } out.close(); }
main.cpp程序
#include"Tspeed.h" int main() { Tspeed(); system("pause"); return 0; }
CMakeLists.txt程序
project(T_CHABU) include_directories(include) add_executable(main_cmake main.cpp src/Tspeed.cpp)
Matlab程序
A=load('Tspeed.txt'); t=A( :,1); p=A( :,2); pd=A( :,3); pdd=A( :,4); figure(2) subplot(3, 1, 1) plot(t, p, 'r', 'LineWidth', 1.5) ylabel('position') grid on subplot(3, 1, 2) plot(t, pd, 'b', 'LineWidth', 1.5) ylabel('velocity') grid on subplot(3, 1, 3) plot(t, pdd, 'g', 'LineWidth', 1.5) ylabel('acceleration') grid on
总结
本篇文章就到这里了,希望能够给你带来帮助,也希望您能够多多关注脚本之家的更多内容!
相关文章
C++找出字符串中出现最多的字符和次数,时间复杂度小于O(n^2)
今天小编就为大家分享一篇关于C++找出字符串中出现最多的字符和次数,时间复杂度小于O(n^2),小编觉得内容挺不错的,现在分享给大家,具有很好的参考价值,需要的朋友一起跟随小编来看看吧2018-12-12
最新评论