C语言实现井字棋详解

#include<stdio.h>
#include<time.h>
#define ROW 3
#define COL 3
//这是对于行和列的初始化
int main()
{
test();
return 0;
}

void menu()
{
printf("输入1开始游戏");
printf("输入0开始游戏");
}

void text()
{
int input = 0;
srand((unsigned int)time(NULL));
do
 {
  switch(input)
  {
   case 1:
     game();
     break;
   case 2:
     printf("退出游戏\n");
     break;
   default:
     printf("选择错误，请重新输入\n");
     break;
  }
 }while(input);
}

void InitBoard(char arr[ROW][COL],int row,int col)
//这里的大写的BOW COL是传入的数组的值，小写的bow col是新的行和列
{
 int i = 0;
 int j = 0;
 for(i = 0;i<row;i++)
 {
  for(j = 0;j<col;j++)
  {
   board[i][j] = ' ';
  }
 }
}

void DisplayBoard(char board[ROW][COL], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
		{
			printf(" %c ", board[i][j]);
			if (j < col - 1)
			{
				printf("|");
			}
		}
		printf("\n");
		if (i < row - 1)
		{
			for (j = 0; j < col; j++)
			{
				printf("---");
					if (j < col - 1)
					{
						printf("|");
					}
			}
		}
		printf("\n");
	}
}

void PlayerMove(char board[ROW][COL],int row,int col)
{
 printf("玩家下棋");
 int x = 0;
 int y = 0;
 while(1)
 {
   scanf("%d %d",&x,&y);
   if(x>=1&&x<=row&&y>=1&&y<=col)//防止输入非法棋子位置
   {
     if(board[x-1][y-1] == ' ')//注意这里的x-1和y-1，玩家在输入的时候输入的假如是1 2，那么给电脑的值就是0 1，这么做是为了与二维数组的下标对应
     {
       board[x-1][y-1] = '*';//注意这里只有一个等号！！！与上面不同，这里是重新定义而上面是相等的时候
       break;
     }
     else
     {
       printf("该坐标被占用，请重新输入\n");
     }
   }
   else
   {
    printf("输入非法，请重新输入");
   }
  }
}

void ComputerMove(char board[ROW][COL],int row,int col)
{
 int x = 0;
 int y = 0;
 printf("电脑下棋\n");
 while(1)
 {
  x = rand()%ROW//此时ROW为3，即x等于0到2的随机值
  y = rand()%COL//此时COL为3，即Y等于0到2的随机值
  if(board[x][y] == '')
  {
    board[x][y] = '#';
    break;
  }
 }
}

char Win(char board[ROW][COL], int row, int col)
{
 int i = 0;
 for (i = 0; i < row; i++)//看一下横着的/竖着的3个符号是否相等，返回一个值让game()中的ret接收
	{
		if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1]!='')
		{
			return board[i][1];
		}
	}
 for (i = 0; i < col; i++)
	{
		if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i]!=' ')
		{
			return board[0][i];
		}
	}
		if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1]!=' ')
		{
			return board[1][1];
		}
 if(1 == FULL(board,row,col))
 {
  return 'Q';//如果经过FULL函数判定棋盘满了那么返回一个Q让ret接收，否则返回C
 }
  return 'C';
}

int Full(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for(i = 0;i<row;i++)
  {
   for(j = 0;j<col;j++)
    {
      if(board[i][j] == ' ')
      {
         return 0;//返回值为0
      }
    }  
  }
  return 1;//如果棋盘满了则返回1
}

void game()
{
	char board[ROW][COL] = {0};
	InitBoard(board, ROW, COL);
	DisplayBoard(board, ROW, COL);
	char ret = 0;//初始化ret，ret为前面说的那个返回值
    //判断输赢的代码
    //玩家赢 - '*'
    //电脑赢 - '#'
    //平均 --- 'Q'
    //继续 ----'C'
	while (1)
	{
		PlayerMove(board, ROW, COL);
		DisplayBoard(board, ROW, COL);
		ret = Win(board, ROW, COL);
		if (ret != 'C')
		{
			break;
		}
		ComputerMove(board, ROW, COL);
		DisplayBoard(board, ROW, COL);
		ret = Win(board, ROW, COL);
		if (ret != 'C')
		{
			break;
		}
	}
 if (ret == '*')//到这里才分别判定返回ret的所有值
	{
		printf("恭喜你你赢了！\n");
	}
	else if(ret == '#')
	{
		printf("很遗憾你输了！\n");
	}
	else
	{
		printf("平局\n");
	}
	printf("\n");
}