Python 十大经典排序算法实现详解

def bubbleSort(arr):
    for i in range(1, len(arr)):
        for j in range(0, len(arr)-i):
            if arr[j] > arr[j+1]:
                arr[j], arr[j + 1] = arr[j + 1], arr[j]
    return arr

def selectionSort(arr):
    for i in range(len(arr) - 1):
        # 记录最小数的索引
        minIndex = i
        for j in range(i + 1, len(arr)):
            if arr[j] < arr[minIndex]:
                minIndex = j
        # i 不是最小数时，将 i 和最小数进行交换
        if i != minIndex:
            arr[i], arr[minIndex] = arr[minIndex], arr[i]
    return arr

def insertionSort(arr):
    for i in range(len(arr)):
        preIndex = i-1
        current = arr[i]
        while preIndex >= 0 and arr[preIndex] > current:
            arr[preIndex+1] = arr[preIndex]
            preIndex-=1
        arr[preIndex+1] = current
    return arr

def shellSort(arr):
    import math
    gap=1
    while(gap < len(arr)/3):
        gap = gap*3+1
    while gap > 0:
        for i in range(gap,len(arr)):
            temp = arr[i]
            j = i-gap
            while j >=0 and arr[j] > temp:
                arr[j+gap]=arr[j]
                j-=gap
            arr[j+gap] = temp
        gap = math.floor(gap/3)
    return arr

def mergeSort(arr):
    import math
    if(len(arr)<2):
        return arr
    middle = math.floor(len(arr)/2)
    left, right = arr[0:middle], arr[middle:]
    return merge(mergeSort(left), mergeSort(right))

def merge(left,right):
    result = []
    while left and right:
        if left[0] <= right[0]:
            result.append(left.pop(0));
        else:
            result.append(right.pop(0));
    while left:
        result.append(left.pop(0));
    while right:
        result.append(right.pop(0));
    return result

def quickSort(arr, left=None, right=None):
    left = 0 if not isinstance(left,(int, float)) else left
    right = len(arr)-1 if not isinstance(right,(int, float)) else right
    if left < right:
        partitionIndex = partition(arr, left, right)
        quickSort(arr, left, partitionIndex-1)
        quickSort(arr, partitionIndex+1, right)
    return arr

def partition(arr, left, right):
    pivot = left
    index = pivot+1
    i = index
    while  i <= right:
        if arr[i] < arr[pivot]:
            swap(arr, i, index)
            index+=1
        i+=1
    swap(arr,pivot,index-1)
    return index-1

def swap(arr, i, j):
    arr[i], arr[j] = arr[j], arr[i]

def buildMaxHeap(arr):
    import math
    for i in range(math.floor(len(arr)/2),-1,-1):
        heapify(arr,i)

def heapify(arr, i):
    left = 2*i+1
    right = 2*i+2
    largest = i
    if left < arrLen and arr[left] > arr[largest]:
        largest = left
    if right < arrLen and arr[right] > arr[largest]:
        largest = right

    if largest != i:
        swap(arr, i, largest)
        heapify(arr, largest)

def swap(arr, i, j):
    arr[i], arr[j] = arr[j], arr[i]

def heapSort(arr):
    global arrLen
    arrLen = len(arr)
    buildMaxHeap(arr)
    for i in range(len(arr)-1,0,-1):
        swap(arr,0,i)
        arrLen -=1
        heapify(arr, 0)
    return arr

def countingSort(arr, maxValue):
    bucketLen = maxValue+1
    bucket = [0]*bucketLen
    sortedIndex =0
    arrLen = len(arr)
    for i in range(arrLen):
        if not bucket[arr[i]]:
            bucket[arr[i]]=0
        bucket[arr[i]]+=1
    for j in range(bucketLen):
        while bucket[j]>0:
            arr[sortedIndex] = j
            sortedIndex+=1
            bucket[j]-=1
    return arr

def bucket_sort(s):
    """桶排序"""
    min_num = min(s)
    max_num = max(s)
    # 桶的大小
    bucket_range = (max_num-min_num) / len(s)
    # 桶数组
    count_list = [ [] for i in range(len(s) + 1)]
    # 向桶数组填数
    for i in s:
        count_list[int((i-min_num)//bucket_range)].append(i)
    s.clear()
    # 回填，这里桶内部排序直接调用了sorted
    for i in count_list:
        for j in sorted(i):
            s.append(j)

if __name__ == __main__ :
    a = [3.2,6,8,4,2,6,7,3]
    bucket_sort(a)
    print(a) # [2, 3, 3.2, 4, 6, 6, 7, 8]

def RadixSort(list):
    i = 0                                    #初始为个位排序
    n = 1                                     #最小的位数置为1（包含0）
    max_num = max(list) #得到带排序数组中最大数
    while max_num > 10**n: #得到最大数是几位数
        n += 1
    while i < n:
        bucket = {} #用字典构建桶
        for x in range(10):
            bucket.setdefault(x, []) #将每个桶置空
        for x in list: #对每一位进行排序
            radix =int((x / (10**i)) % 10) #得到每位的基数
            bucket[radix].append(x) #将对应的数组元素加入到相 #应位基数的桶中
        j = 0
        for k in range(10):
            if len(bucket[k]) != 0: #若桶不为空
                for y in bucket[k]: #将该桶中每个元素
                    list[j] = y #放回到数组中
                    j += 1
        i += 1
return  list