MySQL两个查询如何合并成一个结果详解
MySQL 查询合并
如果我们需要将两个select语句的结果作为一个整体显示出来,我们就需要用到union或者union all关键字。union(或称为联合)的作用是将多个结果合并在一起显示出来。
注意:两个列表中的字段要一样才可以合并(顺序也要一样)
满足条件:
1、两个select查询的列的数量必须相同;
2、每个列的数据类型需要相似;
1.先写两条select
第一条select:
SELECT DATE_FORMAT(add_time, '%Y-%m-%d') as 'add_time', COUNT(add_time) as 'reach_intention' FROM table1 where ## where 条件可以根据自己实际情况来定 DATE_FORMAT(add_time, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 1 month), '%Y-%m-%d') group by DATE_FORMAT(add_time, '%Y-%m-%d')
这是查询出来的结果
第二条select:
select DATE_FORMAT(add_date, '%Y-%m-%d') as 'add_time' , COUNT(add_date) as 'post_release' from table2 where ## where 条件可以根据自己实际情况来定 DATE_FORMAT(add_date, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 1 month), '%Y-%m-%d') group by DATE_FORMAT(add_date, '%Y-%m-%d')
第二条select查询出来的结果
2.合并查询结果
先把两条select用union all连接起来
SELECT DATE_FORMAT(add_time, '%Y-%m-%d') as 'add_time', COUNT(add_time) as 'reach_intention' , '' as 'post_release' FROM table1 where DATE_FORMAT(add_time, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_time, '%Y-%m-%d') UNION ALL select DATE_FORMAT(add_date, '%Y-%m-%d') as 'add_time' , '' as 'reach_intention' , COUNT(add_date) as 'post_release' from table2 where DATE_FORMAT(add_date, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_date, '%Y-%m-%d')
在外层嵌套一个select
## 括号里面放 用 union all 连接的select select * from () test ## 这里要给表起个别名 不然会报 Every derived table must have its own alias 每个派生表都必须有自己的别名
把union all 连接的select 放到括号里面去然后运行
select * from ( SELECT DATE_FORMAT(add_time, '%Y-%m-%d') as 'add_time', COUNT(add_time) as 'reach_intention' , '' as 'post_release' FROM table1 where DATE_FORMAT(add_time, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_time, '%Y-%m-%d') UNION ALL select DATE_FORMAT(add_date, '%Y-%m-%d') as 'add_time' , '' as 'reach_intention' , COUNT(add_date) as 'post_release' from table2 where DATE_FORMAT(add_date, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_date, '%Y-%m-%d') ) test
运行结果
把结果按日期分组排序。
使用 group by 和 order by 关键字
select add_time, sum(reach_intention) as 'reach_intention' , sum(post_release) as 'post_release' from ( SELECT DATE_FORMAT(add_time, '%Y-%m-%d') as 'add_time', COUNT(add_time) as 'reach_intention' , '' as 'post_release' FROM table1 where DATE_FORMAT(add_time, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_time, '%Y-%m-%d') UNION ALL select DATE_FORMAT(add_date, '%Y-%m-%d') as 'add_time' , '' as 'reach_intention' , COUNT(add_date) as 'post_release' from table2 where DATE_FORMAT(add_date, '%Y-%m-%d') > DATE_FORMAT(date_sub(now(), interval 30 day), '%Y-%m-%d') group by DATE_FORMAT(add_date, '%Y-%m-%d') ) test group by test.add_time order by test.add_time desc
结果如下
总结
到此这篇关于MySQL两个查询如何合并成一个结果的文章就介绍到这了,更多相关MySQL两个查询合并一个内容请搜索脚本之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持脚本之家!
相关文章
Centos7.3下mysql5.7.18安装并修改初始密码的方法
这篇文章主要为大家详细介绍了Centos7.3下mysql5.7.18安装并修改初始密码的方法,具有一定的参考价值,感兴趣的小伙伴们可以参考一下2017-06-06
最新评论