python实现将list拼接为一个字符串

>>> str = ' '
>>> seq = ['I','am','superYujx']
>>> print(str.join(seq))

I am superYujx    # 输出结果

>>> str = '_'
>>> seq = ('I','am','superYujx')
>>> print(str.join(seq))

I_am_superYujx    # 输出结果

'''
实现两个list元素1对1拼接
实现结果：1-8-314，99-2-6332
'''
def main():
    list1 = ['0108', '9902', '207']
    list2 = ['314', '6332', '0305']
    list4 = []
    for i in range(0, len(list1)):  #len(list1)获取列表长度
        list1_len1 = len(list1[i])  #元素长度
        if list1_len1 == 4:
            l1_build = list1[i][:2].lstrip("0")  #去除前面的0
            l1_unit = list1[i][3]
        else:
            l1_build = list1[i][:1]
            l1_unit = list1[i][2]
        l2_room = list2[i]
        # list3 = [l1_build + '-' + l1_unit + '-' + l2_room]
        # list4.append(list3[0])
        list3 = l1_build + '-' + l1_unit + '-' + l2_room
        print("list3：", list3, end=",")
        list4.append(list3)
    print('\n')
    print("list4：", list4)
 
 
 
if __name__=="__main__":
    main()