js弹出的对话窗口永远保持居中显示
更新时间:2012年12月15日 17:30:24 作者:
本文将介绍js弹出的对话窗口永远保持居中显示实现方法,需要了解的朋友可以参考下
复制代码 代码如下:
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="utf-8" />
<title></title>
<style type="text/css">
.Div_Scroll {
position:fixed;
margin:-10px;
visibility:hidden;
background-color:#808080;
opacity:0.6;
z-index:99;
}
.Div_Scroll_Content {
position:relative;
margin-top:20%;
width:inherit;
height:inherit;
}
.Div_AlertWindow {
margin:auto;
width:200px;
height:100px;
background-color:lightblue;
border:5px solid #f00;
}
</style>
<script type="text/javascript">
window.onload = function () {
var alertWindow = $("alertParent");
alertWindow.style.width = window.screen.availWidth + "px";
alertWindow.style.height = window.screen.height + "px";
$("Sure").onclick = function () {
alertWindow.style.visibility = "hidden";
}
}
function ShowAlert() {
var alertWindow = $("alertParent");
alertWindow.style.visibility = "visible";
}
$ = function (id) {
return document.getElementById(id);
}
</script>
</head>
<body>
<div id="alertParent" class="Div_Scroll">
<div class="Div_Scroll_Content">
<div id="AlertWindow" class="Div_AlertWindow">
<input type="button" id="Sure" value="close alert Dialog..." />
</div>
</div>
</div>
<div style="height:1300px; padding-top:200px;" >
<input id="alertButton" type="button" onclick="ShowAlert();" value="Show alert Dialog..."/>
</div>
</body>
</html>
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