Java中JSONObject和Map＜String, Object＞的转换方法

public ResponseData<WXModelDTO> getUserInfo(@RequestBody  Map<String, Object> map )

if (map.containsKey("code")) {
            code = map.get("code").toString();
        }

public WXModelDTO getUserInfo(Map<String, Object> map) {
		String code = "";
		String wxCode = "";
		if (map.containsKey("code")) {
			code = map.get("code").toString();
		}

		if (map.containsKey("wxCode")) {
			wxCode = map.get("wxCode").toString();
		}

import org.json.JSONObject;  
  
import java.util.HashMap;  
import java.util.Iterator;  
import java.util.Map;  
  
public class JsonToMap {  
    public static Map<String, Object> toMap(JSONObject obj) {  
        Map<String, Object> map = new HashMap<>();  
        Iterator<String> keysItr = obj.keys();  
        while(keysItr.hasNext()) {  
            String key = keysItr.next();  
            map.put(key, obj.get(key));  
        }  
        return map;  
    }  
  
    // 示例  
    public static void main(String[] args) {  
        JSONObject jsonObject = new JSONObject();  
        jsonObject.put("name", "John Doe");  
        jsonObject.put("age", 30);  
  
        Map<String, Object> map = toMap(jsonObject);  
        System.out.println(map);  
    }  
}

import com.alibaba.fastjson.JSONObject;  
  
import java.util.Map;  
  
public class FastJsonToMap {  
    public static Map<String, Object> toMap(JSONObject jsonObject) {  
        return jsonObject; // 因为fastjson的JSONObject实现了Map接口  
    }  
  
    // 示例  
    public static void main(String[] args) {  
        JSONObject jsonObject = new JSONObject();  
        jsonObject.put("name", "John Doe");  
        jsonObject.put("age", 30);  
  
        Map<String, Object> map = toMap(jsonObject);  
        System.out.println(map);  
    }  
}

import com.alibaba.fastjson.JSONObject;  
  
import java.util.Map;  
  
public class FastMapToJson {  
    public static JSONObject toJson(Map<String, Object> map) {  
        return JSONObject.parseObject(JSONObject.toJSONString(map));  
    }  
  
    // 或者直接使用  
    public static JSONObject toJsonSimple(Map<String, Object> map) {  
        return (JSONObject) JSONObject.toJSON(map);  
    }  
  
    // 示例  
    public static void main(String[] args) {  
        Map<String, Object> map = Map.of("name", "John Doe", "age", 30);  
  
        JSONObject jsonObject = toJsonSimple(map);  
        System.out.println(jsonObject.toJSONString());  
    }  
}