mysqli_store_result (PHP 5) mysqli_store_result (no version information, might be only in CVS) mysqli->store_result -- Transfers a result set from the last query DescriptionProcedural style: mysqli_result mysqli_store_result ( mysqli link ) Object oriented style (method): class mysqli { mysqli_result store_result ( void ) }
Transfers the result set from the last query on the database connection
represented by the link parameter to be used with
the mysqli_data_seek() function.
注:
Although it is always good practice to free the memory used by the result of
a query using the mysqli_free_result() function, when
transfering large result sets using the mysqli_store_result()
this becomes particularly important.
注:
mysqli_store_result() returns FALSE in case the query
didn't return a result set (if the query was, for example an INSERT
statement). This function also returns FALSE if the reading of the
result set failed. You can check if you have got an error by checking
if mysqli_error() doesn't return an empty string, if
mysqli_errno() returns a non zero value, or if
mysqli_field_count() returns a non zero value.
Also possible reason for this function returning FALSE after
successfull call to mysqli_query() can be too large
result set (memory for it cannot be allocated). If
mysqli_field_count() returns a non-zero value, the
statement should have produced a non-empty result set.
返回值
Returns a buffered result object or FALSE if an error occurred.
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