sqlite_current
(PHP 5)
sqlite_current(no version information, might be only in CVS)
SQLiteResult->current(no version information, might be only in CVS)
SQLiteUnbuffered->current -- Fetches the current row from a result set as an array说明
array sqlite_current ( resource result [, int result_type [, bool decode_binary]] )Object oriented style (method):
class SQLiteResult {array current ( [int result_type [, bool decode_binary]] )
}class SQLiteUnbuffered {
array current ( [int result_type [, bool decode_binary]] )
}
sqlite_current() is identical to sqlite_fetch_array() except that it does not advance to the next row prior to returning the data; it returns the data from the current position only.
参数
- result
The SQLite result resource. This parameter is not required when using the object-oriented method.
- result_type
可选的 result_type 参数接受一个常量并决定返回的数组如何索引。用 SQLITE_ASSOC 只会返回关联索引（有名称字段）而 SQLITE_NUM 只会返回数字索引（有序字段数）。SQLITE_BOTH 会同时返回关联和数字索引。 SQLITE_BOTH 是本函数的默认值。
- decode_binary
当 decode_binary 参数设为 TRUE（默认值）时，PHP 将解码那些由 sqlite_escape_string() 编码的数据。通常应保留此值为其默认值，除非在操作其它支持 sqlite 程序建立的数据库时。
返回值
Returns an array of the current row from a result set; FALSE if the current position is beyond the final row.
由 SQLITE_ASSOC 和 SQLITE_BOTH 返回的列名会根据 sqlite.assoc_case 配置选项的值来决定大小写。