stripos

Description

int stripos ( string haystack, string needle [, int offset] )

Returns the numeric position of the first occurrence of needle in the haystack string. Unlike strpos(), stripos() is case-insensitive.

Note that the needle may be a string of one or more characters.

If needle is not found, stripos() will return boolean FALSE.

警告

本函数可能返回布尔值 FALSE，但也可能返回一个与 FALSE 等值的非布尔值，例如 0 或者 ""。请参阅布尔类型章节以获取更多信息。应使用 === 运算符来测试本函数的返回值。

例子 1. stripos() examples
<?php $findme = 'a'; $mystring1 = 'xyz'; $mystring2 = 'ABC'; $pos1 = stripos($mystring1, $findme); $pos2 = stripos($mystring2, $findme); // Nope, 'a' is certainly not in 'xyz' if ($pos1 === false) { echo "The string '$findme' was not found in the string '$mystring1'"; } // Note our use of ===. Simply == would not work as expected // because the position of 'a' is the 0th (first) character. if ($pos2 !== false) { echo "We found '$findme' in '$mystring2' at position $pos2"; } ?>

If needle is not a string, it is converted to an integer and applied as the ordinal value of a character.

The optional offset parameter allows you to specify which character in haystack to start searching. The position returned is still relative to the beginning of haystack.

注: 本函数可安全用于二进制对象。